document.write( "Question 905299: How do I solve the equation: $log_{2x}216=x$
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Algebra.Com's Answer #549151 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
this can be solved graphically.
\n" ); document.write( "i'm not sure if it can be solved algebraically.
\n" ); document.write( "at least i don't know how to do it.
\n" ); document.write( "by graphing i get x = 3 which satisfies the equation because:
\n" ); document.write( "\"log%282x%2C216%29=x\" becomes \"log%286%2C216%29=3\" when \"x+=+3\"
\n" ); document.write( "you can confirm the solution is correct because the law of logs states:
\n" ); document.write( "\"log%28b%2Cx%29+=+y\" if and only if\"+b%5Ey+=+x\"
\n" ); document.write( "by that law:
\n" ); document.write( "\"log%282x%2C216%29+=+x\" if and only if \"%282x%29%5Ex+=+216\"
\n" ); document.write( "when \"x=3\", \"%282x%29%5Ex+=+216\" becomes \"%286%29%5E3+=+216\" which becomes \"216=216\" which is true.\r
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