document.write( "Question 905317: APPLIED PROBLEMS ( need equation and solution)
\n" ); document.write( "A rectangular cardboard is to be made into an open box by cutting a 2cm square piece from each corner and turning up the sides. If the perimeter of the cardboard is 60cm and the volume of the resulting box is 224 cm^3, what are the dimensions of the cardboard.?
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Algebra.Com's Answer #549133 by mananth(16946)\"\" \"About 
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let length of the card board be x
\n" ); document.write( "and the width of the card board be y\r
\n" ); document.write( "\n" ); document.write( "length of box = (x-4) ( 2 cut from each side)
\n" ); document.write( "width of box = (y-4)\r
\n" ); document.write( "\n" ); document.write( "height of box = 2 cm\r
\n" ); document.write( "\n" ); document.write( "volume of box = l*b*h\r
\n" ); document.write( "\n" ); document.write( "224 = (x-4)(y-4)*2
\n" ); document.write( "/2\r
\n" ); document.write( "\n" ); document.write( "112 = xy-4x-4y+16\r
\n" ); document.write( "\n" ); document.write( "96 = xy-4x-4y\r
\n" ); document.write( "\n" ); document.write( "2(x+y) = 60
\n" ); document.write( "x+y=30\r
\n" ); document.write( "\n" ); document.write( "96=xy-4(x+y)\r
\n" ); document.write( "\n" ); document.write( "96=xy-4*30
\n" ); document.write( "96=xy-120
\n" ); document.write( "216 =xy
\n" ); document.write( "x=216/y\r
\n" ); document.write( "\n" ); document.write( "Now x+y =30\r
\n" ); document.write( "\n" ); document.write( "216/y + y =30\r
\n" ); document.write( "\n" ); document.write( "multiply by y
\n" ); document.write( "216+y^2=30y\r
\n" ); document.write( "\n" ); document.write( "y^2-30y+216=0\r
\n" ); document.write( "\n" ); document.write( "y^2-18y-12y+216=0\r
\n" ); document.write( "\n" ); document.write( "y(y-18)-12(y-18)=0\r
\n" ); document.write( "\n" ); document.write( "(y-12)(y-18)=0\r
\n" ); document.write( "\n" ); document.write( "y= 12 OR 18\r
\n" ); document.write( "\n" ); document.write( "The dimensions of the cardboard are 18 by 12 cm\r
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