document.write( "Question 905252: Find the equation of the line that is perpendicular to the line -x+3y=-1 and goes through the point (4,-2) \n" ); document.write( "
Algebra.Com's Answer #549131 by lwsshak3(11628)\"\" \"About 
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Find the equation of the line that is perpendicular to the line -x+3y=-1 and goes through the point (4,-2)
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\n" ); document.write( "Standard form of equation for a line: y=mx+b, m=slope, b=y-intercept
\n" ); document.write( "-x+3y=-1
\n" ); document.write( "3y=x-1
\n" ); document.write( "y=x/3-1/3
\n" ); document.write( "slope=1/3
\n" ); document.write( "..
\n" ); document.write( "slope of perpendicular line=-3 (negative reciprocal)
\n" ); document.write( "equation: y=-3x+b
\n" ); document.write( "solve for b using coordinates of given point (4,-2) on the line
\n" ); document.write( "-2=-3*4+b
\n" ); document.write( "b=10
\n" ); document.write( "equation: y=-3x+10
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