document.write( "Question 76567: Given: (~ p → q) ∨ ~ p
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document.write( "This statement is a:
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document.write( "A. Biconditional statement B. Self-Contradiction
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document.write( "C. Tautology D. Conjunction \n" );
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Algebra.Com's Answer #54912 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! If we let p be false, then the entire disjunction is true since we would have\r \n" ); document.write( "\n" ); document.write( "(~(false) → q) ∨ ~ (false)\r \n" ); document.write( "\n" ); document.write( "(true → q) ∨ true\r \n" ); document.write( "\n" ); document.write( "We can see that a disjunction is true if either side is true. Since the left side is true, the entire disjunction is true.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If we let p be true, then the entire disjunction is also true since we would have\r \n" ); document.write( "\n" ); document.write( "(~(true) → q) ∨ ~ (true)\r \n" ); document.write( "\n" ); document.write( "(false → q) ∨ false\r \n" ); document.write( "\n" ); document.write( "Since a false antecedent means the entire implication is true, the whole left disjunct is true. This means the whole disjunction is true. So for any p (in this case q can be anything), the logical statement is true. This means the statement is a tautology (answer c). \n" ); document.write( " |