document.write( "Question 905243:  Oliver invested $19,000 in two accounts. One earned 4% simple interest and the other 5.5% simple interest. If the interest earned in one year in the 4% account was $228 more than in the interest in the 5.5% account, how much was invested at each rate?
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document.write( "Please solve by writing a system of two equations with two variables. \n" );
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| Algebra.Com's Answer #549119 by richwmiller(17219)     You can put this solution on YOUR website! We know the total amount of money invested. $19000 \n" ); document.write( "x+y=19000, \n" ); document.write( "We know that the difference in the two accounts is $228 \n" ); document.write( "0.055*x-0.04*y=228 \n" ); document.write( "x=19000-y \n" ); document.write( "We substitute for x \n" ); document.write( "0.055*(19000-y)-0.04*y=228 \n" ); document.write( "We multiply out \n" ); document.write( "1045.0-0.055y-0.04*y=228 \n" ); document.write( "We combine like terms. \n" ); document.write( "817.0=0.095*y \n" ); document.write( "Isolate y \n" ); document.write( "817.0 \n" ); document.write( "0.095 \n" ); document.write( "y=8600 at 4% \n" ); document.write( "Calculate x \n" ); document.write( "x=19000-8600 \n" ); document.write( "x=10400 at 5.5% \n" ); document.write( "We check \n" ); document.write( "0.055*10400-0.04*8600=228 \n" ); document.write( "572.0-344=228 \n" ); document.write( "228.0=228 \n" ); document.write( "Since this statement is TRUE and neither amount is negative then it is ok \n" ); document.write( " \n" ); document.write( " |