document.write( "Question 76556: I tried this and came up with 5 but I'm not real sure I have the right answer if it is wrong could you pleae show me how to work this out?
\n" ); document.write( "Solve the equation ln(x+5)-ln(3)=ln(x-3)
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Algebra.Com's Answer #54911 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Solve for x:
\n" ); document.write( "\"ln%28x%2B5%29-ln%283%29+=+ln%28x-3%29\" Apply the quotient rule for logarithms to the left side: \"ln%28M%29-ln%28N%29+=+ln%28M%2FN%29\"
\n" ); document.write( "\"ln%28%28x%2B5%29%2F3%29+=+ln%28x-3%29\" Now, if \"ln%28A%29+=+ln%28B%29\" then A = B, so...
\n" ); document.write( "\"%28x%2B5%29%2F3+=+x-3\" Multiply both sides by 3.
\n" ); document.write( "\"x%2B5+=+3x-9\" Subtract x from both sides.
\n" ); document.write( "\"5+=+2x-9\" Add 9 to both sides.
\n" ); document.write( "\"14+=+2x\" Divide both sides by 2.
\n" ); document.write( "\"x+=+7\"\r
\n" ); document.write( "\n" ); document.write( "Check: Substitute x = 7 into the original equation.
\n" ); document.write( "\"ln%287%2B5%29-ln%283%29+=+ln%287-3%29\"
\n" ); document.write( "\"ln%2812%29-ln%283%29+=+ln%284%29\" Using your calculator to find the natural logs:
\n" ); document.write( "\"ln%2812%29-ln%283%29+=+2.4849-1.0986\" = 1.3863 and...
\n" ); document.write( "\"ln%284%29+=+1.3863\"
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