document.write( "Question 904642: Phyllis invested 38000 dollars, a portion earning a simple interest rate of 4 percent per year and the rest earning a rate of 6 percent per year. After one year the total interest earned on these investments was 1860 dollars. How much money did she invest at each rate?\r
\n" ); document.write( "\n" ); document.write( "Please help me, I'm having a tough time coming up with an equation and finding the answer! Thanks so much for you time. \n" ); document.write( "
Algebra.Com's Answer #549095 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
Total amount of money invested: $38000
\n" ); document.write( "x+y=38000,
\n" ); document.write( "Total yearly interest for the two accounts is: $1860
\n" ); document.write( "0.04*x+0.06*y=1860
\n" ); document.write( "x=38000-y
\n" ); document.write( "Substitute for x
\n" ); document.write( "0.04*(38000-y)+0.06*y=1860
\n" ); document.write( "Multiply out
\n" ); document.write( "1520-0.04y+0.06*y=1860
\n" ); document.write( "Combine like terms.
\n" ); document.write( "0.02*y=340
\n" ); document.write( "Isolate y
\n" ); document.write( "y=$17000.00 at 6%
\n" ); document.write( "x=38000-y
\n" ); document.write( "Calculate x
\n" ); document.write( "x=$21000.00 at 4%
\n" ); document.write( "Check
\n" ); document.write( "0.04*21000+0.06*17000=1860
\n" ); document.write( "840+1020=1860
\n" ); document.write( "1860=1860
\n" ); document.write( "If this statement is TRUE and neither amount is negative then all is well
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