document.write( "Question 905013: A woman invested 4 times as much at 5% as she did at 6%. The total amount of interest she earns in one year from both accounts is $520. How much did she invest at each rate?
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Algebra.Com's Answer #549088 by richwmiller(17219) $\"\"$ $\"About$

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\n" ); document.write( "We know that the interest for the two accounts is $520
\n" ); document.write( "0.05*x+0.06*y=520
\n" ); document.write( "We know that the account at 5% has 4 times the amount at 6%
\n" ); document.write( "We substitute for x
\n" ); document.write( "0.05*(4*y)+0.06*y=520
\n" ); document.write( "We multiply out
\n" ); document.write( "(0.2+0.06)*y=520
\n" ); document.write( "We combine like terms.
\n" ); document.write( "0.26*y=520
\n" ); document.write( "Isolate y
\n" ); document.write( "y= 2000.00
\n" ); document.write( "y=$ 2000.00 at 6%
\n" ); document.write( "Calculate x
\n" ); document.write( "x=4*y
\n" ); document.write( "x=$ 8000.00 at 5%
\n" ); document.write( "Your total is $ 8000.00
\n" ); document.write( "Your total is $ 2000.00
\n" ); document.write( "Your total is $10000.00
\n" ); document.write( "Total invested $ 8000.00 + $ 2000.00=$10000.00
\n" ); document.write( "We check
\n" ); document.write( "0.05* 8000.00+0.06* 2000.00=520
\n" ); document.write( " 400.00+ 120.00=520
\n" ); document.write( "520=520
\n" ); document.write( "Since this statement is TRUE and neither is negative then all is well.
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