document.write( "Question 905169: Please help. I was able to put g(x) = 5x^2 - 30x + 55 into standard form like so g(x) = 5(x - 3)^2+10 but I don't know the value of g or it's max or min
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Algebra.Com's Answer #549080 by Edwin McCravy(20059)![]() ![]() You can put this solution on YOUR website! g(x) = 5(x - 3)^2 + 10 \n" ); document.write( " \r\n" ); document.write( "You have to learn about the graph of equations in the form\r\n" ); document.write( "\r\n" ); document.write( "f(x) = a(x - h)^2 + k, \r\n" ); document.write( "\r\n" ); document.write( "[just like you had to learn about the graph of equation in \r\n" ); document.write( "the form of y = mx+b, which were straight lines.]\r\n" ); document.write( "\r\n" ); document.write( "The graph of equations in the form\r\n" ); document.write( "\r\n" ); document.write( "f(x) = a(x - h)^2 + k\r\n" ); document.write( "\r\n" ); document.write( "are not lines, but are U-shaped curved graph, a right-side up U\r\n" ); document.write( "if \"a\" is a positive number, and the U is upside-down if \"a\"\r\n" ); document.write( "is a negative number.\r\n" ); document.write( "\r\n" ); document.write( "The vertex is the point (h,k). The vertex is the bottom of the \r\n" ); document.write( "U (a MINIMUM pointr) or the top of the upside-down U, (a MAXIMUM\r\n" ); document.write( "point) \r\n" ); document.write( "\r\n" ); document.write( "Notice that the sign of h is changed but the sign of k is not.\r\n" ); document.write( "\r\n" ); document.write( "So the graph of your equation\r\n" ); document.write( "\r\n" ); document.write( "g(x) = 5(x - 3)^2 + 10\r\n" ); document.write( "\r\n" ); document.write( "has a=5, h=3, and k=10\r\n" ); document.write( "\r\n" ); document.write( "So since \"a\" is a positive number 5, the graph is a right side up \r\n" ); document.write( "U-shaped graph with the bottom (MINIMUM) point of the U being \r\n" ); document.write( "the point (h,k) = (3,10).\r\n" ); document.write( "\r\n" ); document.write( "Here's the graph\r\n" ); document.write( "\r\n" ); document.write( "\n" ); document.write( " |