document.write( "Question 76542: I need help I don't know how to set it up. Don't know what to do. This problem is from texbook.
\n" ); document.write( "Fill 10 gallons of premium gas and a small gas can with 2 gallons of regular gas. You pay $13.56. The price of premium gas is 12 cents more per gallon than theprice per gallon for regular gas.\r
\n" ); document.write( "\n" ); document.write( "regular
\n" ); document.write( "2 gal. can
\n" ); document.write( "premium
\n" ); document.write( "10 gal. for car
\n" ); document.write( " = $13.56 \n" ); document.write( "
Algebra.Com's Answer #54908 by checkley75(3666)\"\" \"About 
You can put this solution on YOUR website!
SINCE YOU HAVE 2 GAL. OF REGULAR THAT MEANS YOU HAVE 8 GAL. OF PREMIUM GAS.
\n" ); document.write( "LET X BE THE PRICE OF THE PREMIUM GAS & (X-.12) THE PRICE FOR THE REGULAR GAS.
\n" ); document.write( "13.56=8*X+2(X-.12)
\n" ); document.write( "13.56=8X+2X-.24
\n" ); document.write( "13.56=10X-.24
\n" ); document.write( "10X=13.56+.24
\n" ); document.write( "10X=13.80
\n" ); document.write( "X=13.80/10
\n" ); document.write( "X=1.38 FOR THE PREMIUM GAS
\n" ); document.write( "1.38-.12=1.26 FOR THE REGULAR GAS
\n" ); document.write( "PROOF
\n" ); document.write( "8*1.38+2*1.26=13.56
\n" ); document.write( "11.04+2.52=13.56
\n" ); document.write( "13.56=13.56
\n" ); document.write( " \n" ); document.write( "
\n" );