document.write( "Question 905176: A race car driver starts along a 50-mile race course traveling at an average speed of 90mph. Fifteen minutes later, a second driver starts along the same course at an average speed of 120mph. Will the second car overtake the first car before the drivers reach the end of the course?
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Algebra.Com's Answer #549079 by ankor@dixie-net.com(22740)\"\" \"About 
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A race car driver starts along a 50-mile race course traveling at an average speed of 90mph.
\n" ); document.write( " Fifteen minutes later, a second driver starts along the same course at an average speed of 120mph
\n" ); document.write( "Will the second car overtake the first car before the drivers reach the end of the course?
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\n" ); document.write( "Find how long it takes the 2nd car to overtake the 1st.
\n" ); document.write( "Change 15 min to .25 hrs
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\n" ); document.write( "let t = travel time of the 2nd car
\n" ); document.write( "then
\n" ); document.write( "(t+.25) = travel time of the 1st car
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\n" ); document.write( "When this happens they will have traveled the same distance.
\n" ); document.write( "Write a distance equation; dist = speed*time
\n" ); document.write( "120t = 90(t+.25)
\n" ); document.write( "120t = 90t + 22.5
\n" ); document.write( "120t - 90t = 22.5
\n" ); document.write( "t = 22.5/30
\n" ); document.write( "t = .75 hrs
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\n" ); document.write( "Find how far the 2nd car travels in .75 hr
\n" ); document.write( ".75(120) = 90 mi, obviously he will not overtake the first in a 50 mi race \n" ); document.write( "
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