document.write( "Question 905083: Hello,\r
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\n" ); document.write( "Given the equation xy + 3y = 2x + 1, show that y is a function of x and determine the domain in interval notation.\r
\n" ); document.write( "\n" ); document.write( "Thank you in advance,
\n" ); document.write( "Ryan\r
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Algebra.Com's Answer #549019 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
First solve for y\r
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\n" ); document.write( "\n" ); document.write( "\"xy+%2B+3y+=+2x+%2B+1\"\r
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\n" ); document.write( "\n" ); document.write( "\"y%28x+%2B+3%29+=+2x+%2B+1\"\r
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\n" ); document.write( "\n" ); document.write( "\"y+=+%282x+%2B+1%29%2F%28x+%2B+3%29\"\r
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\n" ); document.write( "\n" ); document.write( "The function is \"y+=+%282x+%2B+1%29%2F%28x+%2B+3%29\" which can also be written as \"f%28x%29+=+%282x+%2B+1%29%2F%28x+%2B+3%29\" (since y = f(x))\r
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\n" ); document.write( "\n" ); document.write( "You cannot divide by zero. So \"x%2B3\", the denominator, can't be equal to zero. Set it equal to zero and solve for x\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B3=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=-3\"\r
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\n" ); document.write( "\n" ); document.write( "The value \"x=-3\" causes the denominator to be zero. Therefore, we must kick it out of the domain. Any other real number is perfectly fine since it doesn't cause a division by zero error.\r
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\n" ); document.write( "\n" ); document.write( "Domain: Set of all real numbers x such that \"x%3C%3E-3\"\r
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\n" ); document.write( "\n" ); document.write( "Domain in interval notation:
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