document.write( "Question 905035: A metallurgist has one alloy containing 21% copper and another containing 60% copper. How many pounds of each alloy must he use to make 54 pounds of a third alloy containing 27% copper? \n" ); document.write( "
Algebra.Com's Answer #548984 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! a+b=54, \n" ); document.write( "21*a+60*b=27*54 \n" ); document.write( "a=54-b \n" ); document.write( "21*(54-b)+60*b=1458 \n" ); document.write( "1134-21b+60*b=1458 \n" ); document.write( "39*b=324 \n" ); document.write( "b=8.30769231 \n" ); document.write( "a=54-b \n" ); document.write( "a=45.6923077 lb. at 21% b=8.30769231 lb. at 60% \n" ); document.write( "check \n" ); document.write( "21*45.6923077+60*8.30769231=27*54 \n" ); document.write( "959.538462+498.461538=1458 \n" ); document.write( "1458.0=1458 \n" ); document.write( "ok \n" ); document.write( " \n" ); document.write( " |