document.write( "Question 904976: how much of a 30% solution would you need to make 50 ml of a 2% solution?\r
\n" ); document.write( "\n" ); document.write( "I need the step by step breakdown please. \n" ); document.write( "
Algebra.Com's Answer #548980 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
from view of solution/acid
\n" ); document.write( "x+y=50,
\n" ); document.write( ".02*50=.30*x
\n" ); document.write( "x=3.33334 acid for 30% acid
\n" ); document.write( "Notice we don't show the water here because it has zero % acid
\n" ); document.write( "We could have shown the water as .02*50=.30*x+0*y
\n" ); document.write( "50-x=46.67 70% water
\n" ); document.write( "check
\n" ); document.write( ".30*3.33333333+0*.46.6666667=2*.50
\n" ); document.write( "1.00+0.0=1.00
\n" ); document.write( "1.=1.0
\n" ); document.write( "ok\r
\n" ); document.write( "\n" ); document.write( "from view of water
\n" ); document.write( "x+y=50
\n" ); document.write( "70x+100y=98*50
\n" ); document.write( "here we show the 50 ml as 98% water (2% acid) so we have 100% water with 70 per cent water (30 % is acid)
\n" ); document.write( "x=3.33333 acid , y=46.6667 water
\n" ); document.write( "check
\n" ); document.write( "0.7*3.33333333+1*46.6666667=0.98*50
\n" ); document.write( "2.33333333+46.6666667=49
\n" ); document.write( "49.0=49
\n" ); document.write( "ok
\n" ); document.write( " \n" ); document.write( "
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