document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=904772>Question 904772</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the measures of 2 supplementary angles if the measure of the larger angle is 44 more then the measure of the smaller angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #548971 by </B><A HREF=/tutors/aboutme.mpl?userid=AlgebraLady88><B>AlgebraLady88(44)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=AlgebraLady88><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=AlgebraLady88><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=548971\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Supplementary angles add up to 180 degrees.\r<BR>\n" );
document.write( "\n" );
document.write( "Let's call the smaller angle , x.<BR>\n" );
document.write( "The bigger angle is 44 degrees more than the measure of the smaller angle. So, that would make it x+ 44\r<BR>\n" );
document.write( "\n" );
document.write( "Since both angles add up to 180 degrees, we have the equation\r<BR>\n" );
document.write( "\n" );
document.write( "x + ( x+ 44) = 180<BR>\n" );
document.write( "2x     + 44  = 180<BR>\n" );
document.write( "2x           = 180 -44<BR>\n" );
document.write( "2x           = 136<BR>\n" );
document.write( "x            = 68 \r<BR>\n" );
document.write( "\n" );
document.write( "So, the smaller angle is 68 degrees and the bigger angle is 68 + 44 = 112 degrees.\r<BR>\n" );
document.write( "\n" );
document.write( "To check,\r<BR>\n" );
document.write( "\n" );
document.write( "68 + 112 = 180  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );