document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=904103>Question 904103</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve.\r<BR>\n" );
document.write( "\n" );
document.write( "2^(x+2) = (1/8) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #548964 by </B><A HREF=/tutors/aboutme.mpl?userid=AlgebraLady88><B>AlgebraLady88(44)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=AlgebraLady88><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=AlgebraLady88><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=548964\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2 ^ ( x+2) = 1/8\r<BR>\n" );
document.write( "\n" );
document.write( "2 ^ (x+2)  = 1 / 2^3<BR>\n" );
document.write( "2 ^ (x+2)  = 2 ^ -3\r<BR>\n" );
document.write( "\n" );
document.write( "Since the bases on both sides are the same, we can take the powers as equal and solve accordingly.\r<BR>\n" );
document.write( "\n" );
document.write( "(x+2) = -3<BR>\n" );
document.write( "x     = -5\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );