document.write( "Question 904925: Solution and Answer please, Thank you!\r
\n" ); document.write( "\n" ); document.write( "- Find the dimensions of a rectangle where the altitude is four seventh of the base and the perimeter is 330 feet.
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Algebra.Com's Answer #548948 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
Usually for rectangle you use length and width. In this case, I'll substitute with altitude and base.
\n" ); document.write( "\"P=2A%2B2B=2%28A%2BB%29=330\"
\n" ); document.write( "\"A%2BB=165\"
\n" ); document.write( "and also,
\n" ); document.write( "\"A=%284%2F7%29B\"
\n" ); document.write( "Substitute,
\n" ); document.write( "\"%284%2F7%29B%2BB=165\"
\n" ); document.write( "\"%284%2F7%29B%2B%287%2F7%29B=165\"
\n" ); document.write( "\"%2811%2F7%29B=165\"
\n" ); document.write( "\"B=165%287%2F11%29\"
\n" ); document.write( "\"B=105\"
\n" ); document.write( "Then,
\n" ); document.write( "\"A=%284%2F7%29105\"
\n" ); document.write( "\"A=60\"
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