document.write( "Question 904833: Use the elimination method to solve each system:\r
\n" ); document.write( "\n" ); document.write( "(7a - 5b = 24
\n" ); document.write( "(12a + 8b = 8
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Algebra.Com's Answer #548930 by richwmiller(17219)\"\" \"About 
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Solved by pluggable solver: Solving a System of Linear Equations by Elimination/Addition

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\n" ); document.write( " Lets start with the given system of linear equations
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\n" ); document.write( " \"7%2Ax-5%2Ay=24\"
\n" ); document.write( " \"12%2Ax%2B8%2Ay=8\"
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\n" ); document.write( " In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for y, we would have to eliminate x (or vice versa).
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\n" ); document.write( " So lets eliminate x. In order to do that, we need to have both x coefficients that are equal but have opposite signs (for instance 2 and -2 are equal but have opposite signs). This way they will add to zero.
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\n" ); document.write( " So to make the x coefficients equal but opposite, we need to multiply both x coefficients by some number to get them to an equal number. So if we wanted to get 7 and 12 to some equal number, we could try to get them to the LCM.
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\n" ); document.write( " Since the LCM of 7 and 12 is 84, we need to multiply both sides of the top equation by 12 and multiply both sides of the bottom equation by -7 like this:
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\n" ); document.write( " \"12%2A%287%2Ax-5%2Ay%29=%2824%29%2A12\" Multiply the top equation (both sides) by 12
\n" ); document.write( " \"-7%2A%2812%2Ax%2B8%2Ay%29=%288%29%2A-7\" Multiply the bottom equation (both sides) by -7
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\n" ); document.write( " So after multiplying we get this:
\n" ); document.write( " \"84%2Ax-60%2Ay=288\"
\n" ); document.write( " \"-84%2Ax-56%2Ay=-56\"
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\n" ); document.write( " Notice how 84 and -84 add to zero (ie \"84%2B-84=0\")
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\n" ); document.write( " Now add the equations together. In order to add 2 equations, group like terms and combine them
\n" ); document.write( " \"%2884%2Ax-84%2Ax%29-60%2Ay-56%2Ay%29=288-56\"
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\n" ); document.write( " \"%2884-84%29%2Ax-60-56%29y=288-56\"
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\n" ); document.write( " \"cross%2884%2B-84%29%2Ax%2B%28-60-56%29%2Ay=288-56\" Notice the x coefficients add to zero and cancel out. This means we've eliminated x altogether.
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\n" ); document.write( " So after adding and canceling out the x terms we're left with:
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\n" ); document.write( " \"-116%2Ay=232\"
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\n" ); document.write( " \"y=232%2F-116\" Divide both sides by \"-116\" to solve for y
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\n" ); document.write( " \"y=-2\" Reduce
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\n" ); document.write( " Now plug this answer into the top equation \"7%2Ax-5%2Ay=24\" to solve for x
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\n" ); document.write( " \"7%2Ax-5%28-2%29=24\" Plug in \"y=-2\"
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\n" ); document.write( " \"7%2Ax%2B10=24\" Multiply
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\n" ); document.write( " \"7%2Ax=24-10\" Subtract \"10\" from both sides
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\n" ); document.write( " \"7%2Ax=14\" Combine the terms on the right side
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\n" ); document.write( " \"cross%28%281%2F7%29%287%29%29%2Ax=%2814%29%281%2F7%29\" Multiply both sides by \"1%2F7\". This will cancel out \"7\" on the left side.
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\n" ); document.write( " \"x=2\" Multiply the terms on the right side
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\n" ); document.write( " So our answer is
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\n" ); document.write( " \"x=2\", \"y=-2\"
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\n" ); document.write( " which also looks like
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\n" ); document.write( " (\"2\", \"-2\")
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\n" ); document.write( " Notice if we graph the equations (if you need help with graphing, check out this solver)
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\n" ); document.write( " \"7%2Ax-5%2Ay=24\"
\n" ); document.write( " \"12%2Ax%2B8%2Ay=8\"
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\n" ); document.write( " we get
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\n" ); document.write( " graph of \"7%2Ax-5%2Ay=24\" (red) \"12%2Ax%2B8%2Ay=8\" (green) (hint: you may have to solve for y to graph these) and the intersection of the lines (blue circle).
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\n" ); document.write( " and we can see that the two equations intersect at (\"2\",\"-2\"). This verifies our answer.

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