document.write( "Question 904912: Please help me with this!\r
\n" ); document.write( "\n" ); document.write( "12x^2-5x-7=0, using completing the square.\r
\n" ); document.write( "\n" ); document.write( "Thank you!
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Algebra.Com's Answer #548928 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
\"+12x%5E2+-+5x+-+7+=+0+\"
\n" ); document.write( "\"+12x%5E2+-+5x+=+7+\"
\n" ); document.write( "\"+x%5E2+-+%285%2F12%29%2Ax+=+7%2F12+\"
\n" ); document.write( "---------------------------
\n" ); document.write( "Take 1/2 the coefficient of the x term,
\n" ); document.write( "square it, and add it to both sides
\n" ); document.write( "\"+x%5E2+-+%285%2F12%29%2Ax+%2B+%285%2F24%29%5E2+=+7%2F12+%2B+%285%2F24%29%5E2+\"
\n" ); document.write( "\"+x%5E2+-+%285%2F12%29%2Ax+%2B+25%2F576+=+336%2F576+%2B+25%2F576+\"
\n" ); document.write( "\"+x%5E2+-+%285%2F12%29%2Ax+%2B+25%2F576+=+361%2F576+\"
\n" ); document.write( "\"+%28+x+-+5%2F24+%29%5E2+=+%28+19%2F24+%29%5E2+\"
\n" ); document.write( "Take the square root of both sides
\n" ); document.write( "\"+x+-+5%2F24+=+19%2F24+\"
\n" ); document.write( "\"+x+=+24%2F24+\"
\n" ); document.write( "\"+x+=+1+\"
\n" ); document.write( "and
\n" ); document.write( "\"+x+=+5%2F24+=+-19%2F24+\"
\n" ); document.write( "\"+x+=+-14%2F24+\"
\n" ); document.write( "\"+x+=+-7%2F12+\"
\n" ); document.write( "----------------
\n" ); document.write( "check:
\n" ); document.write( "\"+%28+x+-+1+%29%2A+%28+x+%2B+7%2F12+%29+\"
\n" ); document.write( "\"+x%5E2+-+x+%2B+%287%2F12%29%2Ax+-+7%2F12+=+0+\"
\n" ); document.write( "\"+x%5E2+-+%285%2F12%29%2Ax+-+7%2F12+=+0+\"
\n" ); document.write( "\"+12x%5E2+-+5x+-+7+=+0+\"
\n" ); document.write( "OK
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