document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=904747>Question 904747</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Brett has 2 gallons of 35% antifreeze. How many gallons of 100% antifreeze should he add to the solution to produce a solution of 50% antifreeze? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #548891 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=548891\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1*x+0.35*2=0.5(2+x)<BR>\n" );
document.write( "1*x+0.7=1+0.5x<BR>\n" );
document.write( "1x-0.5x=1-0.7<BR>\n" );
document.write( "0.5x=0.3<BR>\n" );
document.write( "x=0.6 gal of 100% is added to 2 gal of 35%  to get  2.6 gal  at 50%<BR>\n" );
document.write( "check<BR>\n" );
document.write( "1*0.6+0.35*2=0.5(2+0.6)<BR>\n" );
document.write( "0.6+0.7=0.5(2.6)<BR>\n" );
document.write( "1.3=1.3<BR>\n" );
document.write( "ok<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );