document.write( "Question 904769: please help me solve this equation: one third of a number added to one quarter of a smaller number equals 18. the difference between the two numbers is 26. what are the two numbers??? \n" ); document.write( "
Algebra.Com's Answer #548884 by mananth(16946)\"\" \"About 
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let the numbers be x & y\r
\n" ); document.write( "\n" ); document.write( "I condition\r
\n" ); document.write( "\n" ); document.write( "(1/3)x+(1/4)y =18\r
\n" ); document.write( "\n" ); document.write( "II condition\r
\n" ); document.write( "\n" ); document.write( "x-y 26\r
\n" ); document.write( "\n" ); document.write( "(1/3)x+(1/4)y =18
\n" ); document.write( "LCM of the denominator is 12
\n" ); document.write( "multiply equation by 12\r
\n" ); document.write( "\n" ); document.write( "4x+3y=216\r
\n" ); document.write( "\n" ); document.write( "4 x + 3 y = 216 .............1
\n" ); document.write( "
\n" ); document.write( "1 x -1 y = 26 .............2
\n" ); document.write( "Eliminate y
\n" ); document.write( "multiply (1)by 1
\n" ); document.write( "Multiply (2) by 3
\n" ); document.write( "4 x 3 y = 216
\n" ); document.write( "3 x -3 y = 78
\n" ); document.write( "Add the two equations
\n" ); document.write( "7 x = 294
\n" ); document.write( "/ 7
\n" ); document.write( "x = 42
\n" ); document.write( "plug value of x in (1)
\n" ); document.write( "4 x + 3 y = 216
\n" ); document.write( "168 + 3 y = 216
\n" ); document.write( " 3 y = 216 -168
\n" ); document.write( " 3 y = 48
\n" ); document.write( " y = 16
\n" ); document.write( " \n" ); document.write( "
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