document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=904744>Question 904744</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many liters of an 80% glycol solution must be added to 6 liters of a 25% glycol solution to obtain a 55% solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #548872 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=548872\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 0.8*x+0.25*6=0.55(6+x)<BR>\n" );
document.write( "0.8*x+1.5=3.3+0.55x<BR>\n" );
document.write( "0.8x-0.55x=3.3-1.5<BR>\n" );
document.write( "0.25x=1.8\r<BR>\n" );
document.write( "\n" );
document.write( "x=7.2 liter of 80% is added to 6 liter of 25%  to get  13.2 liter  at 55%<BR>\n" );
document.write( "check<BR>\n" );
document.write( "0.8*7.2+0.25*6=0.55(6+7.2)<BR>\n" );
document.write( "5.76+1.5=0.55(13.2)<BR>\n" );
document.write( "7.26=7.26<BR>\n" );
document.write( "ok<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );