document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=904738>Question 904738</A>: <I><SPAN STYLE=\"word-break: break-all;\">  find the sum of the first 5 terms of the geometric progression for which the first and second terms are 27 and 9 respectively </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #548866 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=548866\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "S=27*(1 - 1/3^5)/(1 - 1/3)<BR>\n" );
document.write( "S=27*(1 - 1/3^5)/(2/3)<BR>\n" );
document.write( "S=9*(1 - 1/3^5)/2<BR>\n" );
document.write( "S=4.5*(1 - 1/3^5)<BR>\n" );
document.write( "S=121/3<BR>\n" );
document.write( "S=40 1/3 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );