document.write( "Question 904675: Car A is traveling at 60 mph, and Car B is traveling at 40 mph. Car B is 5 miles ahead of Car A. After how many minutes and miles will they meet up? \n" ); document.write( "
Algebra.Com's Answer #548845 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! gaining speed 60 -40= 20 mph \n" ); document.write( "headstart 40*0.125 =5 miles \n" ); document.write( "time to catch up 5/20=0.25 hours \n" ); document.write( "time to catch up =15 minutes \n" ); document.write( "algebraic solution \n" ); document.write( "40(t+0.125)=60t \n" ); document.write( "40t+5.0=60t \n" ); document.write( "5.0=60t-40t \n" ); document.write( "5.0=20t \n" ); document.write( "0.25=t\r \n" ); document.write( "\n" ); document.write( ".25*60=15 miles to catch up \n" ); document.write( "The car at 60 mph is going a mile a minute,\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |