document.write( "Question 904675: Car A is traveling at 60 mph, and Car B is traveling at 40 mph. Car B is 5 miles ahead of Car A. After how many minutes and miles will they meet up? \n" ); document.write( "
Algebra.Com's Answer #548845 by richwmiller(17219)\"\" \"About 
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gaining speed 60 -40= 20 mph
\n" ); document.write( "headstart 40*0.125 =5 miles
\n" ); document.write( "time to catch up 5/20=0.25 hours
\n" ); document.write( "time to catch up =15 minutes
\n" ); document.write( "algebraic solution
\n" ); document.write( "40(t+0.125)=60t
\n" ); document.write( "40t+5.0=60t
\n" ); document.write( "5.0=60t-40t
\n" ); document.write( "5.0=20t
\n" ); document.write( "0.25=t\r
\n" ); document.write( "\n" ); document.write( ".25*60=15 miles to catch up
\n" ); document.write( "The car at 60 mph is going a mile a minute,\r
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