document.write( "Question 904645: Please help me! I've been stuck on this problem for a while now and could really use some help.\r
\n" ); document.write( "\n" ); document.write( "Wilma drove at an average speed of 40 mi/h from her home in City A to visit her sister in City B. She stayed in City B for 25 hours, and on the trip back averaged 50 mi/h. She returned home 43 hours after leaving. How many miles is City A from City B?
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Algebra.Com's Answer #548832 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"miles+=+m+\"\r
\n" ); document.write( "\n" ); document.write( "\"+m%2F50+%2B+m%2F40+%2B+25+=+43\" (the two travel times + 25 hours) \r
\n" ); document.write( "\n" ); document.write( " \"m%2F50+%2B+m%2F40+=+43-25\" \r
\n" ); document.write( "\n" ); document.write( "\"m%2F50+%2B+m%2F40+=+18\" (total travel time) \r
\n" ); document.write( "\n" ); document.write( "\"+40m%2F2000+%2B+50m%2F2000+=+18\" (common denominator) \r
\n" ); document.write( "\n" ); document.write( " \"90m%2F2000+=+18\"
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\n" ); document.write( " \"90m+=+18%2A2000+\"\r
\n" ); document.write( "\n" ); document.write( "\"90m+=+36000+\"\r
\n" ); document.write( "\n" ); document.write( "\"m+=+36000%2F90\" \r
\n" ); document.write( "\n" ); document.write( "\"m+=+400\" miles
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