document.write( "Question 901871: A father and his son can do a job in 20 days. The father can do four times as much work as his son in a given amount of time. In how many days can the father do the job alone?\r
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Algebra.Com's Answer #548820 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! 1/x+1/(4x)=1/20 \n" ); document.write( "4/4x+1/(4x)=1/20 \n" ); document.write( "5/4x=1/20 \n" ); document.write( "4x=100 \n" ); document.write( "x=25 days for the father alone \n" ); document.write( "check \n" ); document.write( "1/25+1/100=1/20 \n" ); document.write( "4/100+1/100=5/100 \n" ); document.write( "5/100=5/100 \n" ); document.write( "ok\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |