document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=904455>Question 904455</A>: <I><SPAN STYLE=\"word-break: break-all;\"> x y-2z=7, 2x-3y-2z=0, x-2y-3z=3 How to solve this linear equation by using: Addition method and row equivalent method? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #548793 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=548793\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I am guessing that it should be +y in the first equation<BR>\n" );
document.write( "The answers come out (23/3,22/3,10/-3) with -1y<BR>\n" );
document.write( "and (1,2,-2) with +1y\r<BR>\n" );
document.write( "\n" );
document.write( " x +y-2z=7,<BR>\n" );
document.write( " 2x-3y-2z=0,<BR>\n" );
document.write( " x-2y-3z=3\r<BR>\n" );
document.write( "\n" );
document.write( "1,1,-2,7<BR>\n" );
document.write( "2,-3,-2,0<BR>\n" );
document.write( "1,-2,-3,3\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "add  down (-2) *row 1 to row 2<BR>\n" );
document.write( "1,1,-2,7<BR>\n" );
document.write( "0,-5,2,-14<BR>\n" );
document.write( "1,-2,-3,3\r<BR>\n" );
document.write( "\n" );
document.write( "add  down (-1) *row 1 to row 3<BR>\n" );
document.write( "1,1,-2,7<BR>\n" );
document.write( "0,-5,2,-14<BR>\n" );
document.write( "0,-3,-1,-4\r<BR>\n" );
document.write( "\n" );
document.write( "divide row 2 by -5<BR>\n" );
document.write( "1,1,-2,7<BR>\n" );
document.write( "0,1,2/-5,-14/-5<BR>\n" );
document.write( "0,-3,-1,-4\r<BR>\n" );
document.write( "\n" );
document.write( "add  down (3) *row 2 to row 3<BR>\n" );
document.write( "1,1,-2,7<BR>\n" );
document.write( "0,1,2/-5,14/5<BR>\n" );
document.write( "0,0,11/-5,22/5\r<BR>\n" );
document.write( "\n" );
document.write( "divide row 3 by 11/-5<BR>\n" );
document.write( "1,1,-2,7<BR>\n" );
document.write( "0,1,2/-5,14/5<BR>\n" );
document.write( "0,0,1,-2\r<BR>\n" );
document.write( "\n" );
document.write( "We now have the value for the last variable.<BR>\n" );
document.write( "We will work our way up and get the other solutions.\r<BR>\n" );
document.write( "\n" );
document.write( "add up  (-2/-5) *row 3 to row 2<BR>\n" );
document.write( "1,1,-2,7<BR>\n" );
document.write( "0,1,0,2<BR>\n" );
document.write( "0,0,1,-2\r<BR>\n" );
document.write( "\n" );
document.write( "add up  (2) *row 3 to row 1<BR>\n" );
document.write( "1,1,0,3<BR>\n" );
document.write( "0,1,0,2<BR>\n" );
document.write( "0,0,1,-2\r<BR>\n" );
document.write( "\n" );
document.write( "add up  (-1) *row 2 to row 1<BR>\n" );
document.write( "1,0,0,1<BR>\n" );
document.write( "0,1,0,2<BR>\n" );
document.write( "0,0,1,-2\r<BR>\n" );
document.write( "\n" );
document.write( "final<BR>\n" );
document.write( "1,0,0,1<BR>\n" );
document.write( "0,1,0,2<BR>\n" );
document.write( "0,0,1,-2\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "\"1\",\"2\",\"-2\"<BR>\n" );
document.write( "(1,2,-2)\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );