document.write( "Question 904550: How many gallons fo a 20% acid solution should be mixed with a 30% acid solution to produce 100 gallons of a 23% solution? \n" ); document.write( "
Algebra.Com's Answer #548784 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! a+b=100, \n" ); document.write( "0.2*a+0.3*b=0.23*100 \n" ); document.write( "a=100-b \n" ); document.write( "0.2*(100-b)+0.3*b=23 \n" ); document.write( "20-0.2b+0.3*b=23 \n" ); document.write( "0.1*b=3 \n" ); document.write( "b=30 \n" ); document.write( "a=100-b \n" ); document.write( "a=70 gal at 20% b=30 gal at 30% \n" ); document.write( "check \n" ); document.write( "0.2*70+0.3*30=0.23*100 \n" ); document.write( "14+9=23 \n" ); document.write( "23=23 \n" ); document.write( "ok \n" ); document.write( " \n" ); document.write( " |