document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=904009>Question 904009</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do i figure out -1 2/3 divided by (-10)  ...<BR>\n" );
document.write( "and i have another one i am having problems with -28 5/36 + 16 7/30 <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #548781 by </B><A HREF=/tutors/aboutme.mpl?userid=AlgebraLady88><B>AlgebraLady88(44)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=AlgebraLady88><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=AlgebraLady88><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=548781\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To start, I would recommend dividing by -1 for both numerator and denominator. This gets rid of the negative signs nicely. Then I would turn the mixed number numerator into an improper fraction. Let's work it out below:\r<BR>\n" );
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document.write( "(- 1 2/3 ) / -10\r<BR>\n" );
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document.write( "=  (1 2/3) 10  (here, the negative signs are gone as we have divided by -1)<BR>\n" );
document.write( "=  (5/3) /10   (here, the mixed number numerator is now an improper fraction)<BR>\n" );
document.write( "=   5/3 *1/10  (the reciprocal of 10 is 1/10 )      <BR>\n" );
document.write( "=   1/6\r<BR>\n" );
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document.write( " -28 5/36 + 16 7/30 (turn these into improper fractions as well)<BR>\n" );
document.write( "=   - 1013/36  + 487/30<BR>\n" );
document.write( "Uh oh.. now we have a problem. Some big numbers here ; don't let it worry you. We need to find the LCM of both the denominators, 36 and 30. This is the lowest common multiple; it's just a fancy term to mean the smallest number that is a multiple of both 36 and 30. The LCM makes the denominator the same so that you can work the problem.\r<BR>\n" );
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document.write( "To find LCM, we need to do some prime factorization:\r<BR>\n" );
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document.write( "36 : 12 * 3 = 4 * 3 * 3 = 2 * 2 * 3 * 3<BR>\n" );
document.write( "30 :  6 * 5 = 2 *3 * 5\r<BR>\n" );
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document.write( "Let's arrange the prime factors :\r<BR>\n" );
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document.write( "36 :  2  2  3   3 <BR>\n" );
document.write( "30 :  2     3      5    \r<BR>\n" );
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document.write( "Note: Please put it into columns on your own scratch paper as it won't show up here very clearly. You should have '2's' in the 2 column and '3's' in the 3 column and '5' will be by itself. I will try to upload an illustration if anyone requests it.<BR>\n" );
document.write( "To find the LCM, we use the number in each column; no matter how many times it is repeated, we only use it once. In this case, it would be<BR>\n" );
document.write( "2 * 2 * 3 * 3 * 5 = 180\r<BR>\n" );
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document.write( "Now we can finish the problem:\r<BR>\n" );
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document.write( "- 1013 /36 + 487 / 30<BR>\n" );
document.write( "= - 5065/180 + 2922/ 180<BR>\n" );
document.write( "= - 2143/ 180\r<BR>\n" );
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document.write( "And that's your answer.  2143 is a prime number , so you can't really simplify any more than that.  </SPAN>\n" );
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