document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=904494>Question 904494</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if 15 is decreased by 7 times the sum of 5 and 3 times a number, the result is 12 more than twice the sum of the number and 7. find the number? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #548734 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=548734\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 15-7(3n+5) = (2n+7) + 12<BR>\n" );
document.write( "-20 = 23n + 19<BR>\n" );
document.write( "-39 = 23n<BR>\n" );
document.write( "-39/23 = n<BR>\n" );
document.write( " </SPAN>\n" );
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