document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=904234>Question 904234</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the value of k so that the line containing the points (-3,6) and (4,k) is perpendicular to the line containing the points (-9,-4) and (4,-1).  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #548701 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=548701\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the slopes of the two lines will have -1 as their product<BR>\n" );
document.write( "-9,-4,4,-1<BR>\n" );
document.write( "slope 3/13<BR>\n" );
document.write( "perpendicular slope -13/3<BR>\n" );
document.write( "-3,6,4,k <BR>\n" );
document.write( "x-3-4=-7<BR>\n" );
document.write( "6-k\r<BR>\n" );
document.write( "\n" );
document.write( "(6-k)/-7=-13/3<BR>\n" );
document.write( "3*(6-k)=13*7<BR>\n" );
document.write( "18-3k=91<BR>\n" );
document.write( "-3k=109<BR>\n" );
document.write( "k=-109/3<BR>\n" );
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