document.write( "Question 402848: A woman invested part of $24,000 at 10% interest and the rest at 11%. If her annual interest is $795, how much did she invest at 12%? \n" ); document.write( "
Algebra.Com's Answer #548676 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! She also didn't invest at 10% nor 11 % \n" ); document.write( "24000 at 10% yields $2400 which is more than the $795 interest earned \n" ); document.write( "and so 11% would be even more \n" ); document.write( " |