document.write( "Question 904355: You need 340 mL of a 45% alcohol solution. On hand, you have a 5% alcohol mixture and a 90% alcohol mixture. How much of each mixture will you need to obtain the desired solution? \n" ); document.write( "
Algebra.Com's Answer #548643 by mananth(16946)\"\" \"About 
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percent ---------------- quantity
\n" ); document.write( "Alcohol type I 5.00% ---------------- x ml
\n" ); document.write( "Alcohol type II 90.00% ------ 340 - x ml
\n" ); document.write( "Mixture 45.00% ---------------- 340
\n" ); document.write( "Total 340 ml
\n" ); document.write( "5.00% x + 90.00% ( 340 - x ) = 45.00% * 340
\n" ); document.write( "5 x + 90 ( 340 - x ) = 15300
\n" ); document.write( "5 x + 30600 - 90 x = 15300
\n" ); document.write( "5 x - 90 x = 15300 - -30600
\n" ); document.write( "-85 x = -15300
\n" ); document.write( "/ -85
\n" ); document.write( " x = 180 ml 5.00% Alcohol type I
\n" ); document.write( " 160 ml 90.00% Alcohol type II
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\n" ); document.write( "m.ananth@hotmail.ca
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