document.write( "Question 904355: You need 340 mL of a 45% alcohol solution. On hand, you have a 5% alcohol mixture and a 90% alcohol mixture. How much of each mixture will you need to obtain the desired solution? \n" ); document.write( "
Algebra.Com's Answer #548643 by mananth(16946)![]() ![]() You can put this solution on YOUR website! percent ---------------- quantity \n" ); document.write( "Alcohol type I 5.00% ---------------- x ml \n" ); document.write( "Alcohol type II 90.00% ------ 340 - x ml \n" ); document.write( "Mixture 45.00% ---------------- 340 \n" ); document.write( "Total 340 ml \n" ); document.write( "5.00% x + 90.00% ( 340 - x ) = 45.00% * 340 \n" ); document.write( "5 x + 90 ( 340 - x ) = 15300 \n" ); document.write( "5 x + 30600 - 90 x = 15300 \n" ); document.write( "5 x - 90 x = 15300 - -30600 \n" ); document.write( "-85 x = -15300 \n" ); document.write( "/ -85 \n" ); document.write( " x = 180 ml 5.00% Alcohol type I \n" ); document.write( " 160 ml 90.00% Alcohol type II \n" ); document.write( " \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |