document.write( "Question 904339: suppose that 50 mL of 25% acid are added to x mL of a 70% acid solution. How much 70% acid should be added to the 25% solution to produce a new solution that is 45% acid? \r
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document.write( "Ive tried this so far\r
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document.write( "(50)(0.25)+(x)(0.70)=(x+50)(0.45) but I end up getting that x is 0.025 mL which doesn't seem right. \n" );
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Algebra.Com's Answer #548636 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! For thorough help, study this - http://www.algebra.com/my/Two-Part-Mixture-with-one-material-quantity-unknown.lesson?content_action=show_dev\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "To substitute the given values early, \n" ); document.write( " \n" ); document.write( "Just be careful with the arithmetic and the decimal usage, and you should have no real trouble.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Does that work? \n" ); document.write( " \n" ); document.write( "Yes.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |