document.write( "Question 904339: suppose that 50 mL of 25% acid are added to x mL of a 70% acid solution. How much 70% acid should be added to the 25% solution to produce a new solution that is 45% acid? \r
\n" ); document.write( "\n" ); document.write( "Ive tried this so far\r
\n" ); document.write( "\n" ); document.write( "(50)(0.25)+(x)(0.70)=(x+50)(0.45) but I end up getting that x is 0.025 mL which doesn't seem right.
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Algebra.Com's Answer #548636 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
For thorough help, study this - http://www.algebra.com/my/Two-Part-Mixture-with-one-material-quantity-unknown.lesson?content_action=show_dev\r
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\n" ); document.write( "\n" ); document.write( "To substitute the given values early,
\n" ); document.write( "\"highlight_green%28%2850%2A25%2Bx%2A70%29%2F%28x%2B50%29=45%29\"
\n" ); document.write( "Just be careful with the arithmetic and the decimal usage, and you should have no real trouble.\r
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\n" ); document.write( "\n" ); document.write( "\"%2850%2A25%2Bx%2A70%29%2F%28x%2B50%29=45\"\r
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\n" ); document.write( "\n" ); document.write( "\"%2810%2A25%2B14%2Ax%29%2F%28x%2B50%29=9\"\r
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\n" ); document.write( "\n" ); document.write( "\"14x%2B250=9%28x%2B50%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"14x%2B250=9x%2B450\"\r
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\n" ); document.write( "\n" ); document.write( "\"5x=200\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=200%2F5\"\r
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\n" ); document.write( "\n" ); document.write( "\"highlight%28x=40%29\", this number of mL\r
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\n" ); document.write( "\n" ); document.write( "Does that work?
\n" ); document.write( "\"%2850%2A25%2B40%2A70%29%2F%2840%2B50%29=45\"
\n" ); document.write( "Yes.\r
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