document.write( "Question 904225: how many milliliters of a 4% acid solution and how many milliliters of a 10% acid solution must be mixed to obtain 54mL of a 6% acid solution?
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Algebra.Com's Answer #548573 by richwmiller(17219)\"\" \"About 
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x+y=54,
\n" ); document.write( "0.04*x+0.1*y=0.06*54
\n" ); document.write( "0.04*x+0.1*y=3.24
\n" ); document.write( "x=54-y
\n" ); document.write( "0.04*(54-y)+0.1*y=3.24
\n" ); document.write( "2.16-0.04y+0.1*y=3.24
\n" ); document.write( "0.06*y=1.08
\n" ); document.write( "y=18.0 at 10%
\n" ); document.write( "x=54-y
\n" ); document.write( "x=36.0 at 4%
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\n" ); document.write( "0.04*36+0.1*18.0=0.06*54
\n" ); document.write( "1.44+1.8=3.24
\n" ); document.write( "3.24=3.24
\n" ); document.write( "ok
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