document.write( "Question 903490: Two cyclists leave towns 90mi apart at the same time and travel toward each other. One cyclist travels 8 /mih faster than the other. If they meet in 3 hours, what is the rate of each cyclist? \n" ); document.write( "
Algebra.Com's Answer #548546 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "What a grouch!\r\n" );
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\n" ); document.write( "Two cyclists leave towns 90mi apart at the same time and travel toward each
\n" ); document.write( "other. One cyclist travels 8 mph faster than the other. If they meet in 3
\n" ); document.write( "hours, what is the rate of each cyclist?
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document.write( "                rate  •  time = distance   \r\n" );
document.write( "slower cyclist    x       3        3x\r\n" );
document.write( "faster cyclist   x+8      3      3(x+8)\r\n" );
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document.write( "The sum of their distances must equal the total distance they were\r\n" );
document.write( "apart when they started.\r\n" );
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document.write( "            3x + 3(x+8) = 90\r\n" );
document.write( "           3x + 3x + 24 = 90 \r\n" );
document.write( "                6x + 24 = 90\r\n" );
document.write( "                     8x = 66\r\n" );
document.write( "                      x = \"66%2F8=8.25mph\"\r\n" );
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document.write( "The slower cyclist was going 8.25 mph and the faster one was going\r\n" );
document.write( "8 mph faster or 16.25 mph.\r\n" );
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document.write( "Edwin
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