document.write( "Question 76478: Solve the system by substitution.
\n" ); document.write( "3x-y=-7
\n" ); document.write( "x+y=-9
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Algebra.Com's Answer #54854 by chitra(359)\"\" \"About 
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The given system of equations are: \r
\n" ); document.write( "\n" ); document.write( "3x - y = -7 --------------(1)\r
\n" ); document.write( "\n" ); document.write( "x + y = -9 --------------(2)\r
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\n" ); document.write( "\n" ); document.write( "EQN (2) can be written as: y = -9 - x substituting this is EQN (1), we get: \r
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\n" ); document.write( "\n" ); document.write( "3x - (-9 - x) = -7 \r
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\n" ); document.write( "\n" ); document.write( "3x + 9 + x = -7 \r
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\n" ); document.write( "\n" ); document.write( "4x = - 7 - 9 \r
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\n" ); document.write( "\n" ); document.write( "4x = - 16 \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+-+16%2F4\" \r
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\n" ); document.write( "\n" ); document.write( "==> x = - 4 \r
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\n" ); document.write( "\n" ); document.write( "Substituting this in EQN(1) \r
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\n" ); document.write( "\n" ); document.write( "3(-4) - y = -7 \r
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\n" ); document.write( "\n" ); document.write( "==> -12 - y = -7 \r
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\n" ); document.write( "\n" ); document.write( "==> -y = -7 + 12 \r
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\n" ); document.write( "\n" ); document.write( "==> - y = 5 \r
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\n" ); document.write( "\n" ); document.write( "==> y = -5 \r
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\n" ); document.write( "\n" ); document.write( "Hence, the solutions of the given set of equations are given by: \r
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\n" ); document.write( "\n" ); document.write( "x = -4 and y = -5 are the solutions.
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