document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=904120>Question 904120</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Okay here is the one that I just cant seem to find a starting point.  If 5 times the lesser of two consecutive integers is added to three times the greater, the result is 59. Find the integers. I have 5x-2x=3times =59 and I believe I kind have drove a car over the cliff. I am really struggling with the word problems.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #548535 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=548535\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Okay here is the one that I just cant seem to find a starting point. <BR>\n" );
document.write( "Let's call them n and n+1<BR>\n" );
document.write( " If 5 times the lesser of two consecutive integers 5n<BR>\n" );
document.write( " is added +<BR>\n" );
document.write( " to three times the greater 3*(n+1)<BR>\n" );
document.write( "the result is = <BR>\n" );
document.write( " 59 = 59.<BR>\n" );
document.write( " 5n+3*(n+1)=59<BR>\n" );
document.write( "Find the integers. I have 5x-2x=3times =59 and I believe I kind have drove a car over the cliff. I am really struggling with the word problems.<BR>\n" );
document.write( "Most students have trouble with word problems. <BR>\n" );
document.write( "5n+3*(n+1)=59<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );