document.write( "Question 903884: Imogene's car traveled 336 miles averaging a certain speed. If the car had gone 6 mph faster, the trip would have taken 1 hour less. Find the average speed. \n" ); document.write( "
Algebra.Com's Answer #548479 by ankor@dixie-net.com(22740)\"\" \"About 
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Imogene's car traveled 336 miles averaging a certain speed.
\n" ); document.write( " If the car had gone 6 mph faster, the trip would have taken 1 hour less.
\n" ); document.write( " Find the average speed.
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\n" ); document.write( "let s = the average speed
\n" ); document.write( "then
\n" ); document.write( "(s+6) = the faster speed
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\n" ); document.write( "Write a time equation; time = dist/speed
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\n" ); document.write( "normal speed time - faster speed time = 1 hr
\n" ); document.write( "\"336%2Fs\" - \"336%2F%28%28s%2B6%29%29\" = 1
\n" ); document.write( "multiply equation by s(s+6), cancel the denominators and you have
\n" ); document.write( "336(s+6) - 336s = s(s+6)
\n" ); document.write( "336s + 2016 - 336s = s^2 + 6s
\n" ); document.write( "a quadratic equation
\n" ); document.write( "0 = s^2 + 6s - 2016
\n" ); document.write( "You can use the quadratic equation here, but this will factor to
\n" ); document.write( "(s-42)(s+48) = 0
\n" ); document.write( "the positive solution
\n" ); document.write( "s = 42 mph is the normal speed
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\n" ); document.write( "Confirm this, find the actual time of each scenario
\n" ); document.write( "336/42 = 8 hrs
\n" ); document.write( "336/48 = 7 hrs
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\n" ); document.write( "difference 1 hr
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