document.write( "Question 903884: Imogene's car traveled 336 miles averaging a certain speed. If the car had gone 6 mph faster, the trip would have taken 1 hour less. Find the average speed. \n" ); document.write( "
Algebra.Com's Answer #548479 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Imogene's car traveled 336 miles averaging a certain speed. \n" ); document.write( " If the car had gone 6 mph faster, the trip would have taken 1 hour less. \n" ); document.write( " Find the average speed. \n" ); document.write( ": \n" ); document.write( "let s = the average speed \n" ); document.write( "then \n" ); document.write( "(s+6) = the faster speed \n" ); document.write( ": \n" ); document.write( "Write a time equation; time = dist/speed \n" ); document.write( ": \n" ); document.write( "normal speed time - faster speed time = 1 hr \n" ); document.write( " \n" ); document.write( "multiply equation by s(s+6), cancel the denominators and you have \n" ); document.write( "336(s+6) - 336s = s(s+6) \n" ); document.write( "336s + 2016 - 336s = s^2 + 6s \n" ); document.write( "a quadratic equation \n" ); document.write( "0 = s^2 + 6s - 2016 \n" ); document.write( "You can use the quadratic equation here, but this will factor to \n" ); document.write( "(s-42)(s+48) = 0 \n" ); document.write( "the positive solution \n" ); document.write( "s = 42 mph is the normal speed \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Confirm this, find the actual time of each scenario \n" ); document.write( "336/42 = 8 hrs \n" ); document.write( "336/48 = 7 hrs \n" ); document.write( "-------------- \n" ); document.write( "difference 1 hr \n" ); document.write( " |