document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=904001>Question 904001</A>: <I><SPAN STYLE=\"word-break: break-all;\">  Q1: Adrienne left Montreal biking at 30 kph. Elise left 2 hours later, traveling the same road at 40 kph. At what distance does Elise overtake Adrienne? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #548451 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=548451\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> gaining speed 40 -30= 10 mph<BR>\n" );
document.write( "headstart  30*2 =60 miles<BR>\n" );
document.write( "time to catch up 60/10=6 hours<BR>\n" );
document.write( "algebraic solution<BR>\n" );
document.write( "30(t+2)=40t<BR>\n" );
document.write( "30t+60=40t<BR>\n" );
document.write( "60=40t-30t<BR>\n" );
document.write( "60=10t<BR>\n" );
document.write( "6=t<BR>\n" );
document.write( "distance to meeting 6*40=240 miles\r<BR>\n" );
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document.write( "As much as I like to do these problems <BR>\n" );
document.write( "Submit one at a time and no similar problems.<BR>\n" );
document.write( "Those two problem are the same except for the numbers\r<BR>\n" );
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document.write( " </SPAN>\n" );
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