document.write( "Question 76460: 2x+3y=40 and 2x+2y=20? \n" ); document.write( "
Algebra.Com's Answer #54845 by chitra(359)\"\" \"About 
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The given equations are:\r
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\n" ); document.write( "\n" ); document.write( "2x + 3y = 40 -----------(1) \r
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\n" ); document.write( "\n" ); document.write( "2x + 2y = 20 -----------(2)\r
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\n" ); document.write( "\n" ); document.write( "Subtracting EQN (1) from (2), we get: \r
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\n" ); document.write( "\n" ); document.write( "y = 20 \r
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\n" ); document.write( "\n" ); document.write( "Substituing this in any one of the equations, we get: \r
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\n" ); document.write( "\n" ); document.write( "2x + 2(20) = 20 \r
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\n" ); document.write( "\n" ); document.write( "2x + 40 = 20 \r
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\n" ); document.write( "\n" ); document.write( "2x = 20 - 40 \r
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\n" ); document.write( "\n" ); document.write( "2x = -20 \r
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\n" ); document.write( "\n" ); document.write( "x = - 20/2 \r
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\n" ); document.write( "\n" ); document.write( "x = -10 \r
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\n" ); document.write( "\n" ); document.write( "Hence, the values of x = -10 and y = 20 satisfies both of the equations. \r
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\n" ); document.write( "\n" ); document.write( "Hence, the solution.\r
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