document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=903990>Question 903990</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perpendicular height of a triangle is 3 cm less than the<BR>\n" );
document.write( "length of its base. The area of the triangle is 27 cm2. Form a<BR>\n" );
document.write( "quadratic equation to represent the information and solve to<BR>\n" );
document.write( "find the dimensions of the triangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #548444 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=548444\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A = (1/2)bh<BR>\n" );
document.write( "Question States***<BR>\n" );
document.write( "(1/2)b(b-3) = 27cm^2<BR>\n" );
document.write( "b(b-3) = 54<BR>\n" );
document.write( "b^2 - 3b -54 = 0<BR>\n" );
document.write( "(b+6)(b-9) = 0 (Tossing out the negative solution for unit measure)<BR>\n" );
document.write( "b = 9cm  and h = 6cm <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=9-3 ALIGN=MIDDLE  ALT=\"9-3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "And...checking ***<BR>\n" );
document.write( "54/2 = 27 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );