document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=76441>Question 76441</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0534998461/algebrahomeworkh>College Algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> sandy has a collection of 57 coins worth $10.  They consist of nickels, dimes, and quarters.  The number of quarters is 2 more than 3 times the number of nickels.  HOw many coins of each kind does she have?\r<BR>\n" );
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document.write( "I can't figure this out.  Please help<BR>\n" );
document.write( "on page 386 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #54843 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=54843\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> n+d+q=57...5n+10d+25q=1000...q=3n+2...substituting the value of q from the third equation into the first two equations gives\r<BR>\n" );
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document.write( "A)n+d+3n+2=57...and B)5n+10d+75n+50=1000..multiplying equation A by 10 and subtracting the result from equation B gives\r<BR>\n" );
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document.write( "5n+10d+75n+50-10n-10d-30n-20=1000-570...rearranging and combining terms gives...40n=400 or n=10...so q=32 and d=15 </SPAN>\n" );
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