document.write( "Question 903306: given cot (theta) = 12/5 and 180<(theta)<270, what is cos (theta/2)? \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #548397 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
given cot (theta) = 12/5 and 180<(theta)<270, what is cos (theta/2)?
\n" ); document.write( "***
\n" ); document.write( "you are working with a 5-12-13 reference right triangle in quadrant III in which cos<0
\n" ); document.write( "Use x for theta
\n" ); document.write( "cos x=-12/13
\n" ); document.write( "cos(x/2)=-√((1+cosx)/2)=-√((1-12/13)/2)=-√((1/13)/2)=-√(1/26)=-1/√26
\n" ); document.write( "Check:
\n" ); document.write( "cos x=-12/13 (in Q3)
\n" ); document.write( "x=202.6198˚
\n" ); document.write( "x/2=101.3099˚
\n" ); document.write( "cos(x/2)≈cos(101.3099)≈-0.1961...
\n" ); document.write( "exact value as calculated=-1/√26≈-0.1961...
\n" ); document.write( "
\n" );