document.write( "Question 903894: Mark works out for 50 minutes by biking and jogging. He bikes at an average rate of 1200 feet per minute and jogs at an average rate of 900 feet per minute. He wants to travel a combined 10 miles (1 mile = 5280 feet). How many minutes did Mark spend jogging? \n" ); document.write( "
Algebra.Com's Answer #548383 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
RT=D rate time distance\r
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\n" ); document.write( "\n" ); document.write( "The question should be an accounting of distance. Also account for time.\r
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\n" ); document.write( "\n" ); document.write( "T=D/R;\r
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\n" ); document.write( "\n" ); document.write( "Let x = minutes biking
\n" ); document.write( "Let y = minutes jogging\r
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\n" ); document.write( "\n" ); document.write( "\"1200%2Ax%2B900%2Ay=10%2Amiles%2A5280%28feet%2Fmile%29\"
\n" ); document.write( "AND
\n" ); document.write( "\"x%2By=50\"\r
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\n" ); document.write( "\n" ); document.write( "Simplify the distance sum:
\n" ); document.write( "\"12x%2B9y=528\"
\n" ); document.write( "products of 3,...
\n" ); document.write( "\"4x%2B3y=176\"\r
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\n" ); document.write( "\n" ); document.write( "The system to solve is then,
\n" ); document.write( "\"highlight%28system%284x%2B3y=176%2Cx%2By=50%29%29\".
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