document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=903890>Question 903890</A>: <I><SPAN STYLE=\"word-break: break-all;\"> To provide change for a day's business, a merchant buys $75 worth half dollars, quarters, dimes, and nickels. Altogether there are 360 coins, and the number of half dollars is the same as the number of quarters, and the number of dimes is the same as the number of nickels. Find the number of coins of each investments. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #548378 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=548378\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 50*h+25*q+10*d+5*n=7500<BR>\n" );
document.write( "h+q+d+n=360<BR>\n" );
document.write( "h=q<BR>\n" );
document.write( "d=n<BR>\n" );
document.write( "50*q+25*q+10*d+5*d=7500<BR>\n" );
document.write( "q+q+d+d=360\r<BR>\n" );
document.write( "\n" );
document.write( "75*q+15*d=7500<BR>\n" );
document.write( "2q+2d=360<BR>\n" );
document.write( "q+d=180<BR>\n" );
document.write( "q=180-d<BR>\n" );
document.write( "5*q+1*d=500<BR>\n" );
document.write( "5*(180-d)+1*d=500<BR>\n" );
document.write( "900-5d+d=500<BR>\n" );
document.write( "400=4d<BR>\n" );
document.write( "d=100<BR>\n" );
document.write( "n=100<BR>\n" );
document.write( "q=80<BR>\n" );
document.write( "h=80<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );