document.write( "Question 903887: Meg rowed her boat upstream a distance of 40 miles and then rowed back to the starting point. The total time of the trip was 14 hours. If the rate of the current was 3 mph, find the average speed of the boat relative to the water. \n" ); document.write( "
Algebra.Com's Answer #548376 by mananth(16946)\"\" \"About 
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boat speed x mph Time forward + time return = hours
\n" ); document.write( "current speed 3 mph
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\n" ); document.write( "against current x- 3 mph
\n" ); document.write( "with current x+ 3 mph
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\n" ); document.write( "Distance= 40 miles
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\n" ); document.write( "Time against + time with = 14 hours
\n" ); document.write( "t=d/r
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\n" ); document.write( "40 /( x + 3 ) + 40 /(x - 3 ) = 14
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\n" ); document.write( "LCD = (x - 3 ) ( x + 3 )
\n" ); document.write( "40 *( x - 3 ) + 40 (x + 3 ) = 14 (x^2 - 9 )
\n" ); document.write( "40 x - -120 + 40 x + 120 = 14 ( x ^2 - 9 )
\n" ); document.write( "80 x = 14 x ^2 -126
\n" ); document.write( "14 x ^2 - -80 x - 126 = 0
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\n" ); document.write( "Find the roots of the equation by quadratic formula 5.12
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\n" ); document.write( "a= 14 , b= -80 , c= -126
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\n" ); document.write( "b^2-4ac= 6400 + 7056
\n" ); document.write( "b^2-4ac= 13456
\n" ); document.write( "\"%09sqrt%28%0913456%09%29=%09116%09\" 379.94
\n" ); document.write( "\"x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29\" 0
\n" ); document.write( "\"x1=%28-b%2Bsqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( "x1=( 80 + 116 )/ 28
\n" ); document.write( "x1= 7.00
\n" ); document.write( "\"x2=%28-b-sqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( "x2=( 80 -116 ) / 28
\n" ); document.write( "x2= -1.29
\n" ); document.write( "Ignore negative value
\n" ); document.write( "boat speed 7 mph
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\n" ); document.write( "m.ananth@hotmail.ca
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