document.write( "Question 903887: Meg rowed her boat upstream a distance of 40 miles and then rowed back to the starting point. The total time of the trip was 14 hours. If the rate of the current was 3 mph, find the average speed of the boat relative to the water. \n" ); document.write( "
Algebra.Com's Answer #548376 by mananth(16946)![]() ![]() You can put this solution on YOUR website! boat speed x mph Time forward + time return = hours \n" ); document.write( "current speed 3 mph \n" ); document.write( " \n" ); document.write( "against current x- 3 mph \n" ); document.write( "with current x+ 3 mph \n" ); document.write( " \n" ); document.write( "Distance= 40 miles \n" ); document.write( " \n" ); document.write( "Time against + time with = 14 hours \n" ); document.write( "t=d/r \n" ); document.write( " \n" ); document.write( "40 /( x + 3 ) + 40 /(x - 3 ) = 14 \n" ); document.write( " \n" ); document.write( "LCD = (x - 3 ) ( x + 3 ) \n" ); document.write( "40 *( x - 3 ) + 40 (x + 3 ) = 14 (x^2 - 9 ) \n" ); document.write( "40 x - -120 + 40 x + 120 = 14 ( x ^2 - 9 ) \n" ); document.write( "80 x = 14 x ^2 -126 \n" ); document.write( "14 x ^2 - -80 x - 126 = 0 \n" ); document.write( " \n" ); document.write( "Find the roots of the equation by quadratic formula 5.12 \n" ); document.write( " \n" ); document.write( "a= 14 , b= -80 , c= -126 \n" ); document.write( " \n" ); document.write( "b^2-4ac= 6400 + 7056 \n" ); document.write( "b^2-4ac= 13456 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "x1=( 80 + 116 )/ 28 \n" ); document.write( "x1= 7.00 \n" ); document.write( " \n" ); document.write( "x2=( 80 -116 ) / 28 \n" ); document.write( "x2= -1.29 \n" ); document.write( "Ignore negative value \n" ); document.write( "boat speed 7 mph \n" ); document.write( " \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |