document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=903699>Question 903699</A>: <I><SPAN STYLE=\"word-break: break-all;\">  How many kgs. of tomato costing $1.20 per kg must be mixed with 12 kg of potato costing $ 0.90 per kg so that 50% gain may be obtained by selling the mixture at $1.10 per kg? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #548373 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=548373\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1.20*x+0.90*12=1.10(12+x)<BR>\n" );
document.write( "1.2*x+10.8=13.2+1.1x<BR>\n" );
document.write( "1.2x-1.1x=13.2-10.8<BR>\n" );
document.write( "0.1x=2.4<BR>\n" );
document.write( "x=24 kg of $1.20 is added to 12 kg of $.90  to get  36 kg  at $1.10<BR>\n" );
document.write( "check<BR>\n" );
document.write( "1.2*24+0.9*12=1.1(12+24)<BR>\n" );
document.write( "28.8+10.8=1.1(36)<BR>\n" );
document.write( "39.6=39.6<BR>\n" );
document.write( "ok<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );