document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=76450>Question 76450</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0130519669/algebrahomeworkh>Algebra 1</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> An airplane flew for 4.23 hours with a 25.5kph tailwind. The return flight against the same wind took 4.97 hours. Find the speed of the plane in still air. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #54836 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=54836\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> SINCE DISTANCE=RATE*TIME & WE HAVE THE SAME DISTANCE GOING & RETURNING THE EQUATION IS:<BR>\n" );
document.write( "4.23(X+25.5)=4.97(X-25.5)<BR>\n" );
document.write( "4.23X+107.865=4.97X-126.735<BR>\n" );
document.write( "4.23X-4.97X=-126.735-107.865<BR>\n" );
document.write( "-.74X=-234.6<BR>\n" );
document.write( "X=-234.6/-.74<BR>\n" );
document.write( "X=317.03 KPH. \r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );