document.write( "Question 903845: How much of a(n) 90% orange juice drink must be mixed with 16 gallons of a 30% orange juice drink to obtain a mixture that is 50% orange juice? \r
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document.write( "The amount of 90% orange juice is __ gallons? \n" );
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Algebra.Com's Answer #548358 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! 0.9*x+0.3*16=0.5(16+x) \n" ); document.write( "0.9*x+4.8=8+0.5x \n" ); document.write( "0.9x-0.5x=8-4.8 \n" ); document.write( "0.4x=3.2 \n" ); document.write( "x=8 gallons of 90% is added to 16 gallons of 30% to get 24 gallons at 50% \n" ); document.write( "check \n" ); document.write( "0.9*8+0.3*16=0.5(16+8) \n" ); document.write( "7.2+4.8=0.5(24) \n" ); document.write( "12=12 \n" ); document.write( "ok \n" ); document.write( " \n" ); document.write( " |